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Popular >

integral from 0 to 1 of (x^2+1)

Solution

\int_{0}^{1} (x^{2} + 1) d x

Solution

\frac{4}{3}

+1

Decimal Notation

1.33333 \dots

Solution steps

\int_{0}^{1} x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{2} d x + \int_{0}^{1} 1 d x

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} 1 d x = 1

= \frac{1}{3} + 1

Simplify

\frac{1}{3} + 1 : \frac{4}{3}

= \frac{4}{3}

Popular Examples

(\partial)/(\partial x)(-5y^4sin(5x))

\frac{\partial}{\partial x} (- 5 y^{4} sin (5 x))

(dy)/(dx)=(3x-9)/(2x+8)

\frac{d y}{d x} = \frac{3 x - 9}{2 x + 8}

limit as x approaches 0 of (1-e^{-2x})/x

x \to 0 lim (\frac{1 - e ^{- 2 x}}{x})

(dy)/(dx)=2+e^{-2x+y+1}

\frac{d y}{d x} = 2 + e^{- 2 x + y + 1}

tangent of y=2x-3x^2 tangent of

y = 2 x - 3 x^{2}

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (x^2+1) ?
The integral from 0 to 1 of (x^2+1) is 4/3