What is (\partial)/(\partial x)(ln(9x)) ?

The answer to (\partial)/(\partial x)(ln(9x)) is 1/x

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(\partial)/(\partial x)(ln(9x))

\frac{\partial}{\partial x} (ln (9 x))

\frac{1}{x}

Solution steps

\frac{\partial}{\partial x} (ln (9 x))

Apply the chain rule:

\frac{1}{9 x} \frac{\partial}{\partial x} (9 x)

= \frac{1}{9 x} \frac{\partial}{\partial x} (9 x)

\frac{\partial}{\partial x} (9 x) = 9

= \frac{1}{9 x} \cdot 9

Simplify

\frac{1}{9 x} \cdot 9 : \frac{1}{x}

= \frac{1}{x}

\frac{d}{d x} (\frac{4}{7 x ^{4}})

y^{^{'}} + sin (t) y = sin (t), y (0) = 7

y = x^{2} + 9 x, at x = - 8

\frac{d}{d x} (- cos (e^{x}))

\int_{1}^{6} \frac{1}{2 x + 3 + x} d x

What is (\partial)/(\partial x)(ln(9x)) ?
The answer to (\partial)/(\partial x)(ln(9x)) is 1/x