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Popular Calculus >

y^'=((x+3y))/(2x)

Solution

y^{^{'}} = \frac{( x + 3 y )}{2 x}

Solution

y = - x + c_{1} x^{\frac{3}{2}}

Solution steps

y^{'} (x) = \frac{( x + 3 y )}{2 x}

Solve linear ODE:

y = - x + c_{1} x^{\frac{3}{2}}

y = - x + c_{1} x^{\frac{3}{2}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=((x+3y))/(2x) ?
The solution for y^'=((x+3y))/(2x) is y=-x+c_{1}x^{3/2}