What is (\partial)/(\partial u)(cos(u+v)) ?

The answer to (\partial)/(\partial u)(cos(u+v)) is -sin(u+v)

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(\partial)/(\partial u)(cos(u+v))

\frac{\partial}{\partial u} (cos (u + v))

- sin (u + v)

Solution steps

\frac{\partial}{\partial u} (cos (u + v))

Treat

v

as a constant

Apply the chain rule:

- sin (u + v) \frac{\partial}{\partial u} (u + v)

= - sin (u + v) \frac{\partial}{\partial u} (u + v)

\frac{\partial}{\partial u} (u + v) = 1

= - sin (u + v) \cdot 1

Simplify

= - sin (u + v)

x \to - 4 + lim (\frac{1}{( x + 4 ) ^{2}})

\int \frac{arctan ( 2 x )}{1 + 4 x ^{2}} d x

\frac{1}{12 x ^{2}}, x, \frac{x}{10}

16 y^{^{''''}} + 24 y^{^{''}} + 9 y = 0

\frac{\partial}{\partial x} (x^{3} - 3 y^{2})

What is (\partial)/(\partial u)(cos(u+v)) ?
The answer to (\partial)/(\partial u)(cos(u+v)) is -sin(u+v)