What is laplacetransform 5cos(3t) ?

The answer to laplacetransform 5cos(3t) is (5s)/(s^2+9)

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laplacetransform 5cos(3t)

laplace transform

5 cos (3 t)

\frac{5 s}{s ^{2} + 9}

Solution steps

L {5 cos (3 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 5 L {cos (3 t)}

L {cos (3 t)} : \frac{s}{s ^{2} + 9}

= 5 \cdot \frac{s}{s ^{2} + 9}

Refine

5 \frac{s}{s ^{2} + 9} : \frac{5 s}{s ^{2} + 9}

= \frac{5 s}{s ^{2} + 9}

\int \frac{x + 3 x ^{2}}{y ^{2}} d x

\int \frac{1}{1 - cos ( x )} d x

\frac{\partial}{\partial u} (u + v^{2})

\int_{0}^{5} (x + 1) d x

What is laplacetransform 5cos(3t) ?
The answer to laplacetransform 5cos(3t) is (5s)/(s^2+9)