What is the derivative of xsin(9/x) ?

The derivative of xsin(9/x) is sin(9/x)-(9cos(9/x))/x

What is the first derivative of xsin(9/x) ?

The first derivative of xsin(9/x) is sin(9/x)-(9cos(9/x))/x

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\frac{d}{d x} (x sin (\frac{9}{x}))

sin (\frac{9}{x}) - \frac{9 cos ( \frac{9}{x} )}{x}

Solution steps

\frac{d}{d x} (x sin (\frac{9}{x}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = sin (\frac{9}{x})

= \frac{d x}{d x} sin (\frac{9}{x}) + \frac{d}{d x} (sin (\frac{9}{x})) x

\frac{d x}{d x} = 1

\frac{d}{d x} (sin (\frac{9}{x})) = - \frac{9 cos ( \frac{9}{x} )}{x ^{2}}

= 1 \cdot sin (\frac{9}{x}) + (- \frac{9 cos ( \frac{9}{x} )}{x ^{2}}) x

Simplify

1 \cdot sin (\frac{9}{x}) + (- \frac{9 cos ( \frac{9}{x} )}{x ^{2}}) x : sin (\frac{9}{x}) - \frac{9 cos ( \frac{9}{x} )}{x}

= sin (\frac{9}{x}) - \frac{9 cos ( \frac{9}{x} )}{x}

\int 3 sin (t) + 2 cos (t) + 2 d t

x + 2, \frac{1}{x + 1}, [0, 2]

\int cos^{7} (x) tan^{6} (x) d x

\int (8 - 4 x) e^{2 x} d x

\frac{d y}{d x} - 4 tan (2 x) y = sin (2 x)

What is the derivative of xsin(9/x) ?
The derivative of xsin(9/x) is sin(9/x)-(9cos(9/x))/x
What is the first derivative of xsin(9/x) ?
The first derivative of xsin(9/x) is sin(9/x)-(9cos(9/x))/x