What is the first derivative of 8x+2 ?

The first derivative of 8x+2 is 8

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derivative of 8x+2

\frac{d}{d x} (8 x + 2)

8

Solution steps

\frac{d}{d x} (8 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) + \frac{d}{d x} (2)

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (2) = 0

= 8 + 0

Simplify

= 8

\int 2^{2 x} d x

\frac{d}{d x} (- \frac{24}{x ^{4}})

y = x (x^{2} - 10 x + 30), y = x^{2}

\int x e^{- 125 x} d x

x^{2} + x + 23, 2 x^{2} + 3