What is the derivative of y=(3x-4)^5 ?

The derivative of y=(3x-4)^5 is 15(3x-4)^4

What is the first derivative of y=(3x-4)^5 ?

The first derivative of y=(3x-4)^5 is 15(3x-4)^4

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derivative of

y = (3 x - 4)^{5}

15 (3 x - 4)^{4}

Solution steps

\frac{d}{d x} ((3 x - 4)^{5})

Apply the chain rule:

5 (3 x - 4)^{4} \frac{d}{d x} (3 x - 4)

= 5 (3 x - 4)^{4} \frac{d}{d x} (3 x - 4)

\frac{d}{d x} (3 x - 4) = 3

= 5 (3 x - 4)^{4} \cdot 3

Simplify

= 15 (3 x - 4)^{4}

\frac{d}{d x} (ln (2 x + 1) - x^{2})

f (x) = csc^{2} (x)

\int_{1}^{2} \frac{11}{x ^{3} + 4 x} d x

2 cos^{2} (t)

\int x^{4} e^{x^{5} + 2} d x

What is the derivative of y=(3x-4)^5 ?
The derivative of y=(3x-4)^5 is 15(3x-4)^4
What is the first derivative of y=(3x-4)^5 ?
The first derivative of y=(3x-4)^5 is 15(3x-4)^4