What is the derivative of y= 7/(x^3) ?

The derivative of y= 7/(x^3) is -(21)/(x^4)

What is the first derivative of y= 7/(x^3) ?

The first derivative of y= 7/(x^3) is -(21)/(x^4)

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derivative of

y = \frac{7}{x ^{3}}

- \frac{21}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{7}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 7 (- 3 x^{- 3 - 1})

Simplify

7 (- 3 x^{- 3 - 1}) : - \frac{21}{x ^{4}}

= - \frac{21}{x ^{4}}

\frac{d}{d x} (\frac{1}{π - x})

\frac{y ^{^{'}}}{y - y ^{2}} = \frac{t}{( 1 + t ^{2} )}

f (x) = - 2 x cos (x), (π, 2 π)

n = 0 \sum \infty n! 2^{n}

5 x y (\frac{d y}{d x}) = 4

What is the derivative of y= 7/(x^3) ?
The derivative of y= 7/(x^3) is -(21)/(x^4)
What is the first derivative of y= 7/(x^3) ?
The first derivative of y= 7/(x^3) is -(21)/(x^4)