What is the derivative of 1/(pi-x) ?

The derivative of 1/(pi-x) is 1/((pi-x)^2)

What is the first derivative of 1/(pi-x) ?

The first derivative of 1/(pi-x) is 1/((pi-x)^2)

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\frac{d}{d x} (\frac{1}{π - x})

\frac{1}{( π - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{π - x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((π - x)^{- 1})

Apply the chain rule:

- \frac{1}{( π - x ) ^{2}} \frac{d}{d x} (π - x)

= - \frac{1}{( π - x ) ^{2}} \frac{d}{d x} (π - x)

\frac{d}{d x} (π - x) = - 1

= - \frac{1}{( π - x ) ^{2}} (- 1)

Simplify

= \frac{1}{( π - x ) ^{2}}

\frac{y ^{^{'}}}{y - y ^{2}} = \frac{t}{( 1 + t ^{2} )}

f (x) = - 2 x cos (x), (π, 2 π)

n = 0 \sum \infty n! 2^{n}

5 x y (\frac{d y}{d x}) = 4

x \to 1 lim (ln (8 x) + e^{x})

What is the derivative of 1/(pi-x) ?
The derivative of 1/(pi-x) is 1/((pi-x)^2)
What is the first derivative of 1/(pi-x) ?
The first derivative of 1/(pi-x) is 1/((pi-x)^2)