What is maclaurin (6n-1)(-2x)^n ?

The answer to maclaurin (6n-1)(-2x)^n is \ldots

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maclaurin (6n-1)(-2x)^n

maclaurin

(6 n - 1) (- 2 x)^{n}

\dots

Solution steps

Apply the Maclaurin Formula

= 0 + \frac{\frac{d}{d x} ( ( 6 n - 1 ) ( - 2 x ) ^{n} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( ( 6 n - 1 ) ( - 2 x ) ^{n} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( ( 6 n - 1 ) ( - 2 x ) ^{n} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 0 + \frac{0}{1 !} x + \frac{0}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10} + \dots

Refine

= \dots

\frac{d y}{d x} = k y^{2}

f (x) = 2 x, (8, 4)

\int y^{2} e^{x y} + cos (x) d x

\frac{\partial}{\partial y} (1 - y^{3})

\frac{d y}{d x} = \frac{1 + x}{y}

What is maclaurin (6n-1)(-2x)^n ?
The answer to maclaurin (6n-1)(-2x)^n is \ldots