What is the solution for (dx)/(dt)=2x^2-3x ?

The solution for (dx)/(dt)=2x^2-3x is x=-(3e^{-3t-3c_{1}})/(2(1-e^{-3(t+c_{1))})}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dx)/(dt)=2x^2-3x

\frac{d x}{d t} = 2 x^{2} - 3 x

x = - \frac{3 e ^{- 3 t - 3 c_{1}}}{2 ( 1 - e ^{- 3 (t + c_{1})} )}

Solution steps

\frac{d x}{d t} = 2 x^{2} - 3 x

Solve separable ODE:

x = - \frac{3 e ^{- 3 t - 3 c_{1}}}{2 ( 1 - e ^{- 3 (t + c_{1})} )}

x = - \frac{3 e ^{- 3 t - 3 c_{1}}}{2 ( 1 - e ^{- 3 (t + c_{1})} )}

y = 60 x^{- 9}

\frac{d}{d x} ((\frac{2 y + 3}{4 x + 5})^{2})

f (x) = \frac{4 x}{x - 5}, (7, 14)

\frac{d u}{d x}

4 y^{^{''}} + y = 0

What is the solution for (dx)/(dt)=2x^2-3x ?
The solution for (dx)/(dt)=2x^2-3x is x=-(3e^{-3t-3c_{1}})/(2(1-e^{-3(t+c_{1))})}