What is the limit as x approaches 0 of 1/(x^2)+2 ?

The limit as x approaches 0 of 1/(x^2)+2 is infinity

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limit as x approaches 0 of 1/(x^2)+2

x \to 0 lim (\frac{1}{x ^{2}} + 2)

\infty

Solution steps

x \to 0 lim (\frac{1}{x ^{2}} + 2)

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (\frac{1}{x ^{2}} + 2) = \infty

x \to 0 + lim (\frac{1}{x ^{2}} + 2) = \infty

= \infty

\int \frac{cos ( x )}{x} d x

\int_{0}^{6} 9 sin (x + 1) d x

- 4 (8 x^{2} + 8)^{- 6}

(1 + x)^{^{'}}

f (x) = \frac{1}{7 ( 1 + x ^{2} )}, g (x) = \frac{1}{14} x^{2}

What is the limit as x approaches 0 of 1/(x^2)+2 ?
The limit as x approaches 0 of 1/(x^2)+2 is infinity