What is the (sqrt(1+x))^' ?

The (sqrt(1+x))^' is 1/(2sqrt(1+x))

What is the first (sqrt(1+x))^' ?

The first (sqrt(1+x))^' is 1/(2sqrt(1+x))

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(1 + x)^{^{'}}

\frac{1}{2 1 + x}

Solution steps

(1 + x)^{'}

Apply the chain rule:

\frac{1}{2 1 + x} (1 + x)^{'}

= \frac{1}{2 1 + x} (1 + x)^{'}

(1 + x)^{'} = 1

= \frac{1}{2 1 + x} \cdot 1

Simplify

= \frac{1}{2 1 + x}

f (x) = \frac{1}{7 ( 1 + x ^{2} )}, g (x) = \frac{1}{14} x^{2}

\int \frac{1 + 13 x}{x} d x

x \cdot y \cdot y^{^{'}} = y^{2} + 1

\int - 18 x^{2} d x

x \to 2 - lim (\frac{x}{x - 2})