What is the tangent of f(x)=(ln(x))^4,\at x=7 ?

The tangent of f(x)=(ln(x))^4,\at x=7 is y=(4ln^3(7))/7 x+ln^4(7)-4ln^3(7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(ln(x))^4,\at x=7

tangent of

f (x) = (ln (x))^{4}, at x = 7

y = \frac{4 ln ^{3} ( 7 )}{7} x + ln^{4} (7) - 4 ln^{3} (7)

Solution steps

Find the tangent point:

(7, ln^{4} (7))

Find the slope of

f (x) = (ln (x))^{4} : \frac{df ( x )}{d x} = \frac{4 ln ^{3} ( x )}{x}

Compute the slope of

f (x) = (ln (x))^{4}

x = 7 : m = \frac{4 ln ^{3} ( 7 )}{7}

Find the line with slope m=

\frac{4 ln ^{3} ( 7 )}{7}

and passing through

(7, ln^{4} (7)) : y = \frac{4 ln ^{3} ( 7 )}{7} x + ln^{4} (7) - 4 ln^{3} (7)

y = \frac{4 ln ^{3} ( 7 )}{7} x + ln^{4} (7) - 4 ln^{3} (7)

\frac{\partial}{\partial x} (3 y^{2} - x)

\int (x^{2} + 5)^{3} d x

3 - t

\int cos^{2} (π x) d x

\frac{2 - x e ^{x}}{x + e ^{x}}

What is the tangent of f(x)=(ln(x))^4,\at x=7 ?
The tangent of f(x)=(ln(x))^4,\at x=7 is y=(4ln^3(7))/7 x+ln^4(7)-4ln^3(7)