What is the limit as x approaches-3 of x^2+x-6 ?

The limit as x approaches-3 of x^2+x-6 is 0

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limit as x approaches-3 of x^2+x-6

x \to - 3 lim (x^{2} + x - 6)

0

Solution steps

x \to - 3 lim (x^{2} + x - 6)

Plug in the value

x = - 3

= (- 3)^{2} - 3 - 6

Simplify

(- 3)^{2} - 3 - 6 : 0

= 0

f (x) = x^{3} - 9 x, (3, 0)

t \frac{d y}{d t} = t^{3} + 4 t^{3} y

\int (x^{2} + 3) 5 x d x

f (x) = (3 x^{3} + 2) (x^{4} - 2 x)

\frac{d y}{d x} x + y = (x y)^{\frac{3}{2}}

What is the limit as x approaches-3 of x^2+x-6 ?
The limit as x approaches-3 of x^2+x-6 is 0