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Popular >

y^'=(3y-4x)/(2x-3x)

Solution

y^{^{'}} = \frac{3 y - 4 x}{2 x - 3 x}

Solution

y = x + \frac{c _{1}}{x ^{3}}

Solution steps

y^{'} (x) = \frac{3 y - 4 x}{2 x - 3 x}

Solve linear ODE:

y = x + \frac{c _{1}}{x ^{3}}

y = x + \frac{c _{1}}{x ^{3}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=(3y-4x)/(2x-3x) ?
The solution for y^'=(3y-4x)/(2x-3x) is y=x+(c_{1})/(x^3)