What is the inverse of f(x)=x^2+4x+1 ?

The inverse of f(x)=x^2+4x+1 is -2+sqrt(x+3),-sqrt(x+3)-2

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inverse of f(x)=x^2+4x+1

inverse

f (x) = x^{2} + 4 x + 1

- 2 + x + 3, - x + 3 - 2

Solution steps

y = x^{2} + 4 x + 1

Replace

x

with

y

x = y^{2} + 4 y + 1

Solve for

y, x = y^{2} + 4 y + 1

- 2 + x + 3, - x + 3 - 2

sec (x - \frac{π}{2})

\frac{1}{1 - \frac{1}{x - 2}}

f (x) = \frac{x + 1}{x ^{2} - 4 x + 3}

f (x) = 1 + x^{2}

y = \frac{10 x + 1}{x + 1}

What is the inverse of f(x)=x^2+4x+1 ?
The inverse of f(x)=x^2+4x+1 is -2+sqrt(x+3),-sqrt(x+3)-2