What is the inverse of f(x)=2(x-3)^2+5 ?

The inverse of f(x)=2(x-3)^2+5 is sqrt((x-5)/2)+3,-sqrt((x-5)/2)+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=2(x-3)^2+5

inverse

f (x) = 2 (x - 3)^{2} + 5

\frac{x - 5}{2} + 3, - \frac{x - 5}{2} + 3

Solution steps

y = 2 (x - 3)^{2} + 5

Replace

x

with

y

x = 2 (y - 3)^{2} + 5

Solve for

y, x = 2 (y - 3)^{2} + 5

\frac{x - 5}{2} + 3, - \frac{x - 5}{2} + 3

f (x) = \frac{5 - x}{3 x - 4}

f (x) = - 3 x + 1

f (x) = 2 x^{2} + 7 x - 3

f (x) = 2^{x - 3} - 5

f (x) = 2 π r^{2} + 8 π r

What is the inverse of f(x)=2(x-3)^2+5 ?
The inverse of f(x)=2(x-3)^2+5 is sqrt((x-5)/2)+3,-sqrt((x-5)/2)+3