What is the inverse of f(x)=log_{2}(x)-log_{2}(12) ?

The inverse of f(x)=log_{2}(x)-log_{2}(12) is 3*2^{2+x}

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inverse of f(x)=log_{2}(x)-log_{2}(12)

inverse

f (x) = lo g_{2} (x) - lo g_{2} (12)

3 \cdot 2^{2 + x}

Solution steps

y = lo g_{2} (x) - lo g_{2} (12)

Replace

x

with

y

x = lo g_{2} (y) - lo g_{2} (12)

Solve for

y, x = lo g_{2} (y) - lo g_{2} (12)

3 \cdot 2^{2 + x}

f (x) = \frac{9 x - 3}{9 x + 7}

f (x) = \frac{5 x - 6}{2 x - 1}

f (x) = \frac{x + 4}{x + 8}

f (x) = \frac{( 5 x - 2 )}{3 x + 1}

f (x) = \frac{3}{4} x^{3} + 2

What is the inverse of f(x)=log_{2}(x)-log_{2}(12) ?
The inverse of f(x)=log_{2}(x)-log_{2}(12) is 3*2^{2+x}