What is the inverse of f(x)=(9x-3)/(9x+7) ?

The inverse of f(x)=(9x-3)/(9x+7) is (-3-7x)/(9(-1+x))

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inverse of f(x)=(9x-3)/(9x+7)

inverse

f (x) = \frac{9 x - 3}{9 x + 7}

\frac{- 3 - 7 x}{9 ( - 1 + x )}

Solution steps

y = \frac{9 x - 3}{9 x + 7}

Replace

x

with

y

x = \frac{9 y - 3}{9 y + 7}

Solve for

y, x = \frac{9 y - 3}{9 y + 7}

\frac{- 3 - 7 x}{9 ( - 1 + x )}

f (x) = \frac{5 x - 6}{2 x - 1}

f (x) = \frac{x + 4}{x + 8}

f (x) = \frac{( 5 x - 2 )}{3 x + 1}

f (x) = \frac{3}{4} x^{3} + 2

\frac{4 + x}{1 - x}

What is the inverse of f(x)=(9x-3)/(9x+7) ?
The inverse of f(x)=(9x-3)/(9x+7) is (-3-7x)/(9(-1+x))