What is the inverse of f(x)=(x-3)^4-1 ?

The inverse of f(x)=(x-3)^4-1 is \sqrt[4]{x+1}+3,-\sqrt[4]{x+1}+3

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inverse of f(x)=(x-3)^4-1

inverse

f (x) = (x - 3)^{4} - 1

4 x + 1 + 3, - 4 x + 1 + 3

Solution steps

y = (x - 3)^{4} - 1

Replace

x

with

y

x = (y - 3)^{4} - 1

Solve for

y, x = (y - 3)^{4} - 1

4 x + 1 + 3, - 4 x + 1 + 3

f (x) = \frac{x - 4}{x + 5}

f (x) = \frac{- 8 x + x ^{2} + 12}{12}

f (x) = f (x) = \frac{1}{2} (x - 4)^{2} + 1

4 x^{2} - 28 x + 16 y - 31 = 0

3 + x

What is the inverse of f(x)=(x-3)^4-1 ?
The inverse of f(x)=(x-3)^4-1 is \sqrt[4]{x+1}+3,-\sqrt[4]{x+1}+3