What is the inverse of f(x)=-9sqrt(x-8)+5,x>= 8 ?

The inverse of f(x)=-9sqrt(x-8)+5,x>= 8 is (x^2-10x+25)/(81)+8

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inverse of f(x)=-9sqrt(x-8)+5,x>= 8

inverse

f (x) = - 9 x - 8 + 5, x \geq 8

\frac{x ^{2} - 10 x + 25}{81} + 8

Solution steps

y = - 9 x - 8 + 5

Replace

x

with

y

x = - 9 y - 8 + 5

Solve for

y, x = - 9 y - 8 + 5

\frac{x ^{2} - 10 x + 25}{81} + 8

\frac{1}{2} (e^{x} - e^{- x})

f (x) = a + \frac{1}{x - a}

f (x) = \frac{( x ^{2} )}{3}

f (x) = \frac{s}{s ^{2} - 3 s}

\frac{3 s + 2}{s ^{2} + 2 s + 10}

What is the inverse of f(x)=-9sqrt(x-8)+5,x>= 8 ?
The inverse of f(x)=-9sqrt(x-8)+5,x>= 8 is (x^2-10x+25)/(81)+8