What is the inverse of f(x)=((x^2))/3 ?

The inverse of f(x)=((x^2))/3 is sqrt(3)sqrt(x),-sqrt(3)sqrt(x)

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inverse of f(x)=((x^2))/3

inverse

f (x) = \frac{( x ^{2} )}{3}

3 x, - 3 x

Solution steps

y = \frac{x ^{2}}{3}

Replace

x

with

y

x = \frac{y ^{2}}{3}

Solve for

y, x = \frac{y ^{2}}{3}

3 x, - 3 x

f (x) = \frac{s}{s ^{2} - 3 s}

\frac{3 s + 2}{s ^{2} + 2 s + 10}

f (x) = \frac{( x + 3 )}{4 x - 2}

64 x^{2}

f (x) = - 2 x^{2} + 8 x - 7

What is the inverse of f(x)=((x^2))/3 ?
The inverse of f(x)=((x^2))/3 is sqrt(3)sqrt(x),-sqrt(3)sqrt(x)