What is the inverse of (s-4)/((s+1)*(s+2)) ?

The inverse of (s-4)/((s+1)*(s+2)) is (-3s+1+sqrt(s^2-22s+1))/(2s),(-3s+1-sqrt(s^2-22s+1))/(2s)

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inverse of (s-4)/((s+1)*(s+2))

inverse

\frac{s - 4}{( s + 1 ) \cdot ( s + 2 )}

\frac{- 3 s + 1 + s ^{2} - 22 s + 1}{2 s}, \frac{- 3 s + 1 - s ^{2} - 22 s + 1}{2 s}

Solution steps

y = \frac{s - 4}{( s + 1 ) ( s + 2 )}

Replace

s

with

y

s = \frac{y - 4}{( y + 1 ) ( y + 2 )}

Solve for

y, s = \frac{y - 4}{( y + 1 ) \cdot ( y + 2 )}

\frac{- 3 s + 1 + s ^{2} - 22 s + 1}{2 s}, \frac{- 3 s + 1 - s ^{2} - 22 s + 1}{2 s}

\frac{1}{2} lo g_{10} (6 x)

f (x) = 15 x + 5

f (x) = 15 x + 7

\frac{1}{x - 3}

f (x) = lo g_{2} (x - 2) - 1

What is the inverse of (s-4)/((s+1)*(s+2)) ?
The inverse of (s-4)/((s+1)*(s+2)) is (-3s+1+sqrt(s^2-22s+1))/(2s),(-3s+1-sqrt(s^2-22s+1))/(2s)