What is the inverse of f(x)=18500(0.25-x^2) ?

The inverse of f(x)=18500(0.25-x^2) is sqrt(-0.00005…x+0.25),-sqrt(-0.00005…x+0.25)

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inverse of f(x)=18500(0.25-x^2)

inverse

f (x) = 18500 (0.25 - x^{2})

- 0.00005 \dots x + 0.25, - - 0.00005 \dots x + 0.25

Solution steps

y = 18500 (0.25 - x^{2})

Replace

x

with

y

x = 18500 (0.25 - y^{2})

Solve for

y, x = 18500 (0.25 - y^{2})

- 0.00005 \dots x + 0.25, - - 0.00005 \dots x + 0.25

f (x) = lo g_{7} (1 - sin (x))

f (x) = - 16 x^{2} + 100 x

g (x) = 2 x^{2} - 12 x + 13, x \leq 1

\frac{( s + 4 )}{( s + 1 ) ( s + 2 )}

\frac{( x - 1 )}{x + 1}

What is the inverse of f(x)=18500(0.25-x^2) ?
The inverse of f(x)=18500(0.25-x^2) is sqrt(-0.00005…x+0.25),-sqrt(-0.00005…x+0.25)