What is the inverse of f(x)=(-x^2)/(-4+x^2) ?

The inverse of f(x)=(-x^2)/(-4+x^2) is (2sqrt(x)sqrt(x+1))/(x+1),-(2sqrt(x)sqrt(x+1))/(x+1)

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inverse of f(x)=(-x^2)/(-4+x^2)

inverse

f (x) = \frac{- x ^{2}}{- 4 + x ^{2}}

\frac{2 x x + 1}{x + 1}, - \frac{2 x x + 1}{x + 1}

Solution steps

y = \frac{- x ^{2}}{- 4 + x ^{2}}

Replace

x

with

y

x = \frac{- y ^{2}}{- 4 + y ^{2}}

Solve for

y, x = \frac{- y ^{2}}{- 4 + y ^{2}}

\frac{2 x x + 1}{x + 1}, - \frac{2 x x + 1}{x + 1}

f (x) = - 2 lo g_{4} (x)

f (x) = \frac{20}{x}

f (x) = 1 3 2 + 3 x

f (x) = x^{2} + 7 x + 6

f (x) = 3 (x + 1)^{2} + 2

What is the inverse of f(x)=(-x^2)/(-4+x^2) ?
The inverse of f(x)=(-x^2)/(-4+x^2) is (2sqrt(x)sqrt(x+1))/(x+1),-(2sqrt(x)sqrt(x+1))/(x+1)