What is the inverse of f(x)= 1/4 (x^2-4x+4) ?

The inverse of f(x)= 1/4 (x^2-4x+4) is 2(sqrt(x)+1),2(-sqrt(x)+1)

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inverse of f(x)= 1/4 (x^2-4x+4)

inverse

f (x) = \frac{1}{4} (x^{2} - 4 x + 4)

2 (x + 1), 2 (- x + 1)

Solution steps

y = \frac{1}{4} (x^{2} - 4 x + 4)

Replace

x

with

y

x = \frac{1}{4} (y^{2} - 4 y + 4)

Solve for

y, x = \frac{1}{4} (y^{2} - 4 y + 4)

2 (x + 1), 2 (- x + 1)

f (x) = \frac{( 7 - 14 x ) 1}{2}

f (x) = \frac{- x ^{2}}{- 4 + x ^{2}}

f (x) = - 2 lo g_{4} (x)

f (x) = \frac{20}{x}

f (x) = 1 3 2 + 3 x

What is the inverse of f(x)= 1/4 (x^2-4x+4) ?
The inverse of f(x)= 1/4 (x^2-4x+4) is 2(sqrt(x)+1),2(-sqrt(x)+1)