What is the inverse of f(x)=1\sqrt[3]{2+3x} ?

The inverse of f(x)=1\sqrt[3]{2+3x} is (x^3-2)/3

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inverse of f(x)=1\sqrt[3]{2+3x}

inverse

f (x) = 1 3 2 + 3 x

\frac{x ^{3} - 2}{3}

Solution steps

y = 1 \cdot 3 2 + 3 x

Replace

x

with

y

x = 1 \cdot 3 2 + 3 y

Solve for

y, x = 1 3 2 + 3 y

\frac{x ^{3} - 2}{3}

f (x) = x^{2} + 7 x + 6

f (x) = 3 (x + 1)^{2} + 2

f (x) = \frac{20 + 0.4 x}{100 + x}

f (x) = \frac{3 3 x + 1}{5}

y = \frac{x + 1}{x - 1}

What is the inverse of f(x)=1\sqrt[3]{2+3x} ?
The inverse of f(x)=1\sqrt[3]{2+3x} is (x^3-2)/3