What is the inverse of f(x)= 1/(sqrt(x^2-4)) ?

The inverse of f(x)= 1/(sqrt(x^2-4)) is (sqrt(1+4x^2))/x ,-(sqrt(1+4x^2))/x

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inverse of f(x)= 1/(sqrt(x^2-4))

inverse

f (x) = \frac{1}{x ^{2} - 4}

\frac{1 + 4 x ^{2}}{x}, - \frac{1 + 4 x ^{2}}{x}

Solution steps

y = \frac{1}{x ^{2} - 4}

Replace

x

with

y

x = \frac{1}{y ^{2} - 4}

Solve for

y, x = \frac{1}{y ^{2} - 4}

\frac{1 + 4 x ^{2}}{x}, - \frac{1 + 4 x ^{2}}{x}

f (x) = lo g_{3} ((x - 1)^{2})

f (x) = \frac{8}{7 + x ^{2}}

f (x) = 9 - 2 x^{2}

f (x) = 2.6

What is the inverse of f(x)= 1/(sqrt(x^2-4)) ?
The inverse of f(x)= 1/(sqrt(x^2-4)) is (sqrt(1+4x^2))/x ,-(sqrt(1+4x^2))/x