What is the inverse of f(x)=x^2+4x-4 ?

The inverse of f(x)=x^2+4x-4 is -2+sqrt(x+8),-sqrt(x+8)-2

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inverse of f(x)=x^2+4x-4

inverse

f (x) = x^{2} + 4 x - 4

- 2 + x + 8, - x + 8 - 2

Solution steps

y = x^{2} + 4 x - 4

Replace

x

with

y

x = y^{2} + 4 y - 4

Solve for

y, x = y^{2} + 4 y - 4

- 2 + x + 8, - x + 8 - 2

f (x) = 3 - 2^{2 - x}

f (x) = 1 + x^{2}

f (x) = \frac{5 x}{x - 4}

f (x) = \frac{2 - x ^{2}}{7}

f (x) = \frac{1}{x ^{2} - 9}

What is the inverse of f(x)=x^2+4x-4 ?
The inverse of f(x)=x^2+4x-4 is -2+sqrt(x+8),-sqrt(x+8)-2