What is the inverse of y=sqrt(3.5-5x^2)-0.3 ?

The inverse of y=sqrt(3.5-5x^2)-0.3 is sqrt(-(100x^2+60x-341)/(500)),-sqrt(-(100x^2+60x-341)/(500))

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inverse of y=sqrt(3.5-5x^2)-0.3

inverse

y = 3.5 - 5 x^{2} - 0.3

- \frac{100 x ^{2} + 60 x - 341}{500}, - - \frac{100 x ^{2} + 60 x - 341}{500}

Solution steps

y = 3.5 - 5 x^{2} - 0.3

Replace

x

with

y

x = 3.5 - 5 y^{2} - 0.3

Solve for

y, x = 3.5 - 5 y^{2} - 0.3

- \frac{100 x ^{2} + 60 x - 341}{500}, - - \frac{100 x ^{2} + 60 x - 341}{500}

f (x) = x + 2 - 3

f (x) = 3 8 - 3 x

- \frac{1}{4} x - 2

x^{2} + x + 3

x^{2} + 4 + 1

What is the inverse of y=sqrt(3.5-5x^2)-0.3 ?
The inverse of y=sqrt(3.5-5x^2)-0.3 is sqrt(-(100x^2+60x-341)/(500)),-sqrt(-(100x^2+60x-341)/(500))