What is the inverse of f(x)=((x-3))/(x-2) ?

The inverse of f(x)=((x-3))/(x-2) is (-3+2x)/(x-1)

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inverse of f(x)=((x-3))/(x-2)

inverse

f (x) = \frac{( x - 3 )}{x - 2}

\frac{- 3 + 2 x}{x - 1}

Solution steps

y = \frac{x - 3}{x - 2}

Replace

x

with

y

x = \frac{y - 3}{y - 2}

Solve for

y, x = \frac{y - 3}{y - 2}

\frac{- 3 + 2 x}{x - 1}

2 x^{2} + 8 x - 10

\frac{5}{s ^{2} - 3 s + 3}

g (s) = 65 t

f (x) = \frac{3}{x - 3} + 1

f (x) = 2 - e^{x + 3}

What is the inverse of f(x)=((x-3))/(x-2) ?
The inverse of f(x)=((x-3))/(x-2) is (-3+2x)/(x-1)