What is the inverse of sqrt((2y+6)/(3y+2)) ?

The inverse of sqrt((2y+6)/(3y+2)) is (6-2y^2)/(3y^2-2)

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inverse of sqrt((2y+6)/(3y+2))

inverse

\frac{2 y + 6}{3 y + 2}

\frac{6 - 2 y ^{2}}{3 y ^{2} - 2}

Solution steps

y = \frac{2 y + 6}{3 y + 2}

Replace

y

with

y

y = \frac{2 y + 6}{3 y + 2}

Solve for

y, y = \frac{2 y + 6}{3 y + 2}

\frac{6 - 2 y ^{2}}{3 y ^{2} - 2}

f (x) = f (x) = x^{2} + 2

f (x) = \frac{3 - 4 x}{5 x + 1}

\frac{2 s - 8}{s ^{2} - 4 s - 4}

y = - 4.9 (x + 3)^{2} + 45.8

f (x) = \frac{x + 6}{2}

What is the inverse of sqrt((2y+6)/(3y+2)) ?
The inverse of sqrt((2y+6)/(3y+2)) is (6-2y^2)/(3y^2-2)