What is the inverse of f(x)=f(x)=sqrt(x^3-5) ?

The inverse of f(x)=f(x)=sqrt(x^3-5) is cube root of x^2+5

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inverse of f(x)=f(x)=sqrt(x^3-5)

inverse

f (x) = f (x) = x^{3} - 5

Solution steps

y = x^{3} - 5

Replace

x

with

y

x = y^{3} - 5

Solve for

y, x = y^{3} - 5

g (x) = 2 x^{2} - 4 x + 8

f (x) = - \frac{2}{3} (x + 3)

f (x) = f (x) (x)^{- 1} (x) = (\frac{6}{5}) x - 9

f (x) = \frac{4 ^{x} - 1}{4 ^{x} + 1}

5 x^{2} - 3

What is the inverse of f(x)=f(x)=sqrt(x^3-5) ?
The inverse of f(x)=f(x)=sqrt(x^3-5) is cube root of x^2+5