What is the inverse of f(x)=f(x)(x)^{-1}(x)=(6/5)x-9 ?

The inverse of f(x)=f(x)(x)^{-1}(x)=(6/5)x-9 is (5x+45)/6

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inverse of f(x)=f(x)(x)^{-1}(x)=(6/5)x-9

inverse

f (x) = f (x) (x)^{- 1} (x) = (\frac{6}{5}) x - 9

\frac{5 x + 45}{6}

Solution steps

y = \frac{6}{5} x - 9

Replace

x

with

y

x = \frac{6}{5} y - 9

Solve for

y, x = \frac{6}{5} y - 9

\frac{5 x + 45}{6}

f (x) = \frac{4 ^{x} - 1}{4 ^{x} + 1}

5 x^{2} - 3

\frac{1}{9 - x ^{2}}

f (x) = 2 x^{2} - 5 x

f (x) = - 4 x - 2

What is the inverse of f(x)=f(x)(x)^{-1}(x)=(6/5)x-9 ?
The inverse of f(x)=f(x)(x)^{-1}(x)=(6/5)x-9 is (5x+45)/6