What is the inverse of g(x)=2x^2-4x+8 ?

The inverse of g(x)=2x^2-4x+8 is (4+sqrt(8x-48))/4 ,(4-sqrt(8x-48))/4

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inverse of g(x)=2x^2-4x+8

inverse

g (x) = 2 x^{2} - 4 x + 8

\frac{4 + 8 x - 48}{4}, \frac{4 - 8 x - 48}{4}

Solution steps

y = 2 x^{2} - 4 x + 8

Replace

x

with

y

x = 2 y^{2} - 4 y + 8

Solve for

y, x = 2 y^{2} - 4 y + 8

\frac{4 + 8 x - 48}{4}, \frac{4 - 8 x - 48}{4}

f (x) = - \frac{2}{3} (x + 3)

f (x) = f (x) (x)^{- 1} (x) = (\frac{6}{5}) x - 9

f (x) = \frac{4 ^{x} - 1}{4 ^{x} + 1}

5 x^{2} - 3

\frac{1}{9 - x ^{2}}

What is the inverse of g(x)=2x^2-4x+8 ?
The inverse of g(x)=2x^2-4x+8 is (4+sqrt(8x-48))/4 ,(4-sqrt(8x-48))/4