What is the inverse of f(x)=(12x-3)/(x+6)+1 ?

The inverse of f(x)=(12x-3)/(x+6)+1 is (3-6x)/(x-13)

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inverse of f(x)=(12x-3)/(x+6)+1

inverse

f (x) = \frac{12 x - 3}{x + 6} + 1

\frac{3 - 6 x}{x - 13}

Solution steps

y = \frac{12 x - 3}{x + 6} + 1

Replace

x

with

y

x = \frac{12 y - 3}{y + 6} + 1

Solve for

y, x = \frac{12 y - 3}{y + 6} + 1

\frac{3 - 6 x}{x - 13}

(2 x + 3)^{\frac{1}{5}}

f (x) = 80 e^{0.2 t}

y = x (1 + x)

lo g_{10} (\frac{2}{x + 1})

f (x) = \frac{( 4 x - 2 )}{3 x + 1}

What is the inverse of f(x)=(12x-3)/(x+6)+1 ?
The inverse of f(x)=(12x-3)/(x+6)+1 is (3-6x)/(x-13)