What is the inverse of f(x)=80e^{0.2t} ?

The inverse of f(x)=80e^{0.2t} is (ln(t/(80)))/(0.2)

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inverse of f(x)=80e^{0.2t}

inverse

f (x) = 80 e^{0.2 t}

\frac{ln ( \frac{t}{80} )}{0.2}

Solution steps

x = 80 e^{0.2 t}

Replace

t

with

x

t = 80 e^{0.2 x}

Solve for

x, t = 80 e^{0.2 x}

\frac{ln ( \frac{t}{80} )}{0.2}

y = x (1 + x)

lo g_{10} (\frac{2}{x + 1})

f (x) = \frac{( 4 x - 2 )}{3 x + 1}

f (x) = x^{2} - 8 x + 17

f (x) = x^{2} - 8 x + 18

What is the inverse of f(x)=80e^{0.2t} ?
The inverse of f(x)=80e^{0.2t} is (ln(t/(80)))/(0.2)