What is the inverse of f(x)=x^2-3x+9 ?

The inverse of f(x)=x^2-3x+9 is (3+sqrt(4x-27))/2 ,(3-sqrt(4x-27))/2

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inverse of f(x)=x^2-3x+9

inverse

f (x) = x^{2} - 3 x + 9

\frac{3 + 4 x - 27}{2}, \frac{3 - 4 x - 27}{2}

Solution steps

y = x^{2} - 3 x + 9

Replace

x

with

y

x = y^{2} - 3 y + 9

Solve for

y, x = y^{2} - 3 y + 9

\frac{3 + 4 x - 27}{2}, \frac{3 - 4 x - 27}{2}

\frac{x + 9}{3}

f (x) = 3 - 8 x^{2}

f (x) = x^{2} - 3 x + 6

f (- 8) = \frac{X + 1}{X + 10}

f (x) = \frac{( x + 4 )}{( x + 6 )}

What is the inverse of f(x)=x^2-3x+9 ?
The inverse of f(x)=x^2-3x+9 is (3+sqrt(4x-27))/2 ,(3-sqrt(4x-27))/2