What is the inverse of f(x)=8+sqrt(4x-3) ?

The inverse of f(x)=8+sqrt(4x-3) is (x^2-16x+67)/4

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inverse of f(x)=8+sqrt(4x-3)

inverse

f (x) = 8 + 4 x - 3

\frac{x ^{2} - 16 x + 67}{4}

Solution steps

y = 8 + 4 x - 3

Replace

x

with

y

x = 8 + 4 y - 3

Solve for

y, x = 8 + 4 y - 3

\frac{x ^{2} - 16 x + 67}{4}

f (x) = x^{3} + 3

y = \frac{- 9 x - 3}{4}

y = - x^{3}

f (x) = 8 + 4 x - 4

y = x^{2} - 6 x + 11

What is the inverse of f(x)=8+sqrt(4x-3) ?
The inverse of f(x)=8+sqrt(4x-3) is (x^2-16x+67)/4