What is the inverse of f(x)=sqrt(-5+x),x>= 5 ?

The inverse of f(x)=sqrt(-5+x),x>= 5 is x^2+5

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inverse of f(x)=sqrt(-5+x),x>= 5

inverse

f (x) = - 5 + x, x \geq 5

x^{2} + 5

Solution steps

y = - 5 + x

Replace

x

with

y

x = - 5 + y

Solve for

y, x = - 5 + y

x^{2} + 5

4 x^{2} + 8 x + 17

f (x) = 2 (3^{x}) - 4

f (x) = 0.005

f (x) = f (x) = \frac{( 1 )}{( x + 2 )}

y = (ln (x))^{3}

What is the inverse of f(x)=sqrt(-5+x),x>= 5 ?
The inverse of f(x)=sqrt(-5+x),x>= 5 is x^2+5