What is the inverse of f(x)=f(x)=6sqrt(x)+7-9,x>=-7 ?

The inverse of f(x)=f(x)=6sqrt(x)+7-9,x>=-7 is (x^2)/(36)+x/9+1/9

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inverse of f(x)=f(x)=6sqrt(x)+7-9,x>=-7

inverse

f (x) = f (x) = 6 x + 7 - 9, x \geq - 7

\frac{x ^{2}}{36} + \frac{x}{9} + \frac{1}{9}

Solution steps

y = 6 x + 7 - 9

Replace

x

with

y

x = 6 y + 7 - 9

Solve for

y, x = 6 y + 7 - 9

\frac{x ^{2}}{36} + \frac{x}{9} + \frac{1}{9}

6 lo g_{2} (2^{x} - 7)

8 (2 x + 10)^{2} + 3

f (x) = 5 + 8 y

f (x) = x^{2} - 8 x + 10, x \geq 4

f (x) = x^{2} + 3 x - 21

What is the inverse of f(x)=f(x)=6sqrt(x)+7-9,x>=-7 ?
The inverse of f(x)=f(x)=6sqrt(x)+7-9,x>=-7 is (x^2)/(36)+x/9+1/9