What is the inverse of+(x^2-7x+10)/(x+2) ?

The inverse of+(x^2-7x+10)/(x+2) is (7+x+sqrt(x^2+22x+9))/2 ,(7+x-sqrt(x^2+22x+9))/2

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inverse of+(x^2-7x+10)/(x+2)

inverse

+ \frac{x ^{2} - 7 x + 10}{x + 2}

\frac{7 + x + x ^{2} + 22 x + 9}{2}, \frac{7 + x - x ^{2} + 22 x + 9}{2}

Solution steps

y = \frac{x ^{2} - 7 x + 10}{x + 2}

Replace

x

with

y

x = \frac{y ^{2} - 7 y + 10}{y + 2}

Solve for

y, x = + \frac{y ^{2} - 7 y + 10}{y + 2}

\frac{7 + x + x ^{2} + 22 x + 9}{2}, \frac{7 + x - x ^{2} + 22 x + 9}{2}

y = \frac{3 x}{5 x - 9}

s^{4}

2 lo g_{5} (x^{3} + 17)

f (x) = \frac{x + 1}{- 2 x + 1}

f (x) = 1 - 5 x - 5

What is the inverse of+(x^2-7x+10)/(x+2) ?
The inverse of+(x^2-7x+10)/(x+2) is (7+x+sqrt(x^2+22x+9))/2 ,(7+x-sqrt(x^2+22x+9))/2