What is the inverse of h(x)=sqrt((2-x)/(5-x)) ?

The inverse of h(x)=sqrt((2-x)/(5-x)) is (2-5x^2)/(-x^2+1)

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inverse of h(x)=sqrt((2-x)/(5-x))

inverse

h (x) = \frac{2 - x}{5 - x}

\frac{2 - 5 x ^{2}}{- x ^{2} + 1}

Solution steps

y = \frac{2 - x}{5 - x}

Replace

x

with

y

x = \frac{2 - y}{5 - y}

Solve for

y, x = \frac{2 - y}{5 - y}

\frac{2 - 5 x ^{2}}{- x ^{2} + 1}

(\frac{e ^{x} + 9}{2})^{\frac{1}{3}}

\frac{1}{x ^{2} - 16}

f (x) = \frac{4 x - 5}{x - 1}

f (x) = ln (- x + 1)

f (x) = 1 - 3 x^{2}

What is the inverse of h(x)=sqrt((2-x)/(5-x)) ?
The inverse of h(x)=sqrt((2-x)/(5-x)) is (2-5x^2)/(-x^2+1)