What is the inverse of sqrt(2-3x^2) ?

The inverse of sqrt(2-3x^2) is sqrt(-(x^2-2)/3),-sqrt(-(x^2-2)/3)

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inverse of sqrt(2-3x^2)

inverse

2 - 3 x^{2}

- \frac{x ^{2} - 2}{3}, - - \frac{x ^{2} - 2}{3}

Solution steps

y = 2 - 3 x^{2}

Replace

x

with

y

x = 2 - 3 y^{2}

Solve for

y, x = 2 - 3 y^{2}

- \frac{x ^{2} - 2}{3}, - - \frac{x ^{2} - 2}{3}

f (x) = 3 x^{2} + 3

\frac{13}{x ^{2}}

\frac{16 a ^{4} + 16 a}{a ^{2} + 1 - a}

y = ln (\frac{x}{x - 1})

f (x) = \frac{8 x - 7}{7 x + 3}

What is the inverse of sqrt(2-3x^2) ?
The inverse of sqrt(2-3x^2) is sqrt(-(x^2-2)/3),-sqrt(-(x^2-2)/3)