What is the inverse of f(x)=(x-15)^2,x>= 15 ?

The inverse of f(x)=(x-15)^2,x>= 15 is sqrt(x)+15,-sqrt(x)+15

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inverse of f(x)=(x-15)^2,x>= 15

inverse

f (x) = (x - 15)^{2}, x \geq 15

x + 15, - x + 15

Solution steps

y = (x - 15)^{2}

Replace

x

with

y

x = (y - 15)^{2}

Solve for

y, x = (y - 15)^{2}

x + 15, - x + 15

f (x) = - 2 (x + 2)^{\frac{1}{3}} - 1

y = 2 x - 8

- \frac{3}{s ^{2} - 6 s + 13}

\frac{2 x ^{2} + 1}{3 x - 2}

3 x^{2} - 27

What is the inverse of f(x)=(x-15)^2,x>= 15 ?
The inverse of f(x)=(x-15)^2,x>= 15 is sqrt(x)+15,-sqrt(x)+15