What is the inverse of f(x)=(sqrt(7x-1))/2 ?

The inverse of f(x)=(sqrt(7x-1))/2 is (4x^2+1)/7

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inverse of f(x)=(sqrt(7x-1))/2

inverse

f (x) = \frac{7 x - 1}{2}

\frac{4 x ^{2} + 1}{7}

Solution steps

y = \frac{7 x - 1}{2}

Replace

x

with

y

x = \frac{7 y - 1}{2}

Solve for

y, x = \frac{7 y - 1}{2}

\frac{4 x ^{2} + 1}{7}

y + 5 = lo g_{0.7} (3 x - 2)

\frac{d}{d} 5 x - 9 (1.2)

\frac{( x + 3 )}{( x + 13 )}

\frac{9 n ^{6} - 11}{8}

- 7 lo g_{6} (- 3 x)

What is the inverse of f(x)=(sqrt(7x-1))/2 ?
The inverse of f(x)=(sqrt(7x-1))/2 is (4x^2+1)/7