What is the inverse of y+5=log_{0.7}(3x-2) ?

The inverse of y+5=log_{0.7}(3x-2) is (0.7^{x+5}+2)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y+5=log_{0.7}(3x-2)

inverse

y + 5 = lo g_{0.7} (3 x - 2)

\frac{0. 7 ^{x + 5} + 2}{3}

Solution steps

y = lo g_{0.7} (3 x - 2) - 5

Replace

x

with

y

x = lo g_{0.7} (3 y - 2) - 5

Solve for

y, x = lo g_{0.7} (3 y - 2) - 5

\frac{0. 7 ^{x + 5} + 2}{3}

\frac{d}{d} 5 x - 9 (1.2)

\frac{( x + 3 )}{( x + 13 )}

\frac{9 n ^{6} - 11}{8}

- 7 lo g_{6} (- 3 x)

f (x) = f (x) = 12 x 3 - 9 x 2 - 108 x + 1

What is the inverse of y+5=log_{0.7}(3x-2) ?
The inverse of y+5=log_{0.7}(3x-2) is (0.7^{x+5}+2)/3