What is the inverse of-7log_{6}(-3x) ?

The inverse of-7log_{6}(-3x) is -3^{(-x-7)/7}*2^{-x/7}

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inverse of-7log_{6}(-3x)

inverse

- 7 lo g_{6} (- 3 x)

- 3^{\frac{- x - 7}{7}} \cdot 2^{- \frac{x}{7}}

Solution steps

y = - 7 lo g_{6} (- 3 x)

Replace

x

with

y

x = - 7 lo g_{6} (- 3 y)

Solve for

y, x = - 7 lo g_{6} (- 3 y)

- 3^{\frac{- x - 7}{7}} \cdot 2^{- \frac{x}{7}}

f (x) = f (x) = 12 x 3 - 9 x 2 - 108 x + 1

f (x) = \frac{9 x + 8}{8 x - 3}

y = \frac{3}{4} \frac{2}{3} x - \frac{4}{9}

f (x) = 2^{(x)} + 5

f (x) = \frac{8}{x - 4}

What is the inverse of-7log_{6}(-3x) ?
The inverse of-7log_{6}(-3x) is -3^{(-x-7)/7}*2^{-x/7}